『算法-ACM竞赛-数学-数论』HDU 2136(素数筛选法)

『算法-ACM 竞赛-数学-数论』HDU 2136(素数筛选法)

Everybody knows any number can be combined by the prime number.
Now, your task is telling me what position of the largest prime factor.
The position of prime 2 is 1, prime 3 is 2, and prime 5 is 3, etc.
Specially, LPF(1) = 0.
Input
Each line will contain one integer n(0 < n < 1000000).
Output
Output the LPF(n).
Sample Input
1
2
3
4
5
Sample Output
0
1
2
1
3

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
#include <iostream>
#include <cmath>
#include <iomanip>
#include <algorithm>
using namespace std;
const int MAX = 1000000;
int prime[MAX];
int mark[MAX];

void init()
{
for (int i = 2, n = 1; i < MAX; i++)
{
if (!prime[i])
{
mark[i] = n++;
for (int j = i; j < MAX; j = j + i)
prime[j] = i;
}
}
}
int main()
{
int n;
init();
while (~scanf("%d", &n))
{
printf("%d\n", mark[prime[n]]);
}
return 0;
}

『算法-ACM竞赛-数学-数论』HDU 2136(素数筛选法)
https://chiamzhang.github.io/2024/06/29/『算法-ACM竞赛-数学-数论』HDU 2136(素数筛选法)/
Author
Chiam
Posted on
June 29, 2024
Licensed under